If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+4x-22.5=0
a = 1; b = 4; c = -22.5;
Δ = b2-4ac
Δ = 42-4·1·(-22.5)
Δ = 106
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{106}}{2*1}=\frac{-4-\sqrt{106}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{106}}{2*1}=\frac{-4+\sqrt{106}}{2} $
| (3+2x)x=702 | | 8l=4 | | -4(-6-8x)=88 | | B=7/2(j-25) | | -8x+4=-25x+1 | | 3w^-8w+4=0 | | -x+2=4x-5 | | -8(2+6k)=224 | | (3x+4)-(x-8)=0 | | 16=64n | | 4=64n | | −27x−56=−23 | | (3x+4)+(x-8)=0 | | 278=-u+119 | | 12x+6=107 | | (3x-4)+(x-8)=0 | | x^2-4x-22.5=0 | | 293=160-v | | 9x-15=8x | | -x+233=49 | | 5x-4=57 | | 25n^2-285n+810=0 | | 6v+6(-4+v)=126 | | 7=98/u | | 8(3-(5+6x))-4x=-18+2(1-26x) | | 3(5x+2)-4=27 | | 4.x-11=3.x-8 | | 170-v=285 | | 3x+15-9=2(x+20 | | 2.x+1=6.x-19 | | n-3(-5+4n)=81 | | 4x+3=10x+11 |